5x^2=1620

Solution for 5x^2=1620 equation:

5x^2=1620

We move all terms to the left:

5x^2-(1620)=0

a = 5; b = 0; c = -1620;
Δ = b2-4ac
Δ = 02-4·5·(-1620)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*5}=\frac{-180}{10}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*5}=\frac{180}{10}
=18
$